練習問題1(文字式と数の乗法・除法4)解答
(1) 9χ-12χ=(9−12)χ
=−3χ
答え −3χ
(2) 4-8χ+7χ-5=-(8-7)χ+4−5
=−χ−1
答え −χ−1
(3) -χ+8-(3χ-6)=-χ+8-3χ+6
=-χ-3χ+8+6
=−4χ+14
答え −4χ+14
(4) 3/4a×(-12)=3a×(-3)
=-9a
答え -9a
(5) -9χ÷(-3/7)=-9χ×(-7/3)
=-3χ×(-7)
=21χ
答え 21χ
(6) 10(χ/5-1/2)=10×χ/5+10×(-1/2)
=2χ-5
答え 2χ-5
(7) 2/3(-12χ+18)=2/3×(-12χ)+2/3×18
=2×(-4χ)+2×6
=-8χ+12
答え -8χ+12
(8) (20χ+16)÷4/5=20χ×5/4+16×5/4
=5χ×5+4×5
=25χ+20
答え 25χ+20
(9) -32×3χ-6/8=-4×(3χ-6)
=-4×3χ-4×(-6)
=-12χ+24
答え -12χ+24
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